The value of term independent of x in the expansion (2x^2 - 1/x)^12 - Sarthaks eConnect | Largest Online Education Community
The term independent of x in the binomial expansion of (1 - 1/x + 3x^5)(2x^2 - 1/x)^8 is : - Sarthaks eConnect | Largest Online Education Community
![Find the term independent of x in the expansion of the following expressions: (1 + x + 2x^3) ( 32x^2 - 13x )^9 Enter 1 if answer is 1754 otherwise enter 0. Find the term independent of x in the expansion of the following expressions: (1 + x + 2x^3) ( 32x^2 - 13x )^9 Enter 1 if answer is 1754 otherwise enter 0.](https://haygot.s3.amazonaws.com/questions/1414669_1666828_ans_84978291b49d41e0989261119da4893b.jpg)
Find the term independent of x in the expansion of the following expressions: (1 + x + 2x^3) ( 32x^2 - 13x )^9 Enter 1 if answer is 1754 otherwise enter 0.
![combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange](https://i.stack.imgur.com/ZApvE.jpg)
combinatorics - Find the coefficient of term independent of x in (1+x+7/x)^7 - Mathematics Stack Exchange
![Find the term independent of x in the expansion of 〖〖(6x^2– 5/x^2 )]8. Binomial Theorem-Maths-Class-11 Find the term independent of x in the expansion of 〖〖(6x^2– 5/x^2 )]8. Binomial Theorem-Maths-Class-11](https://www.nextgurukul.in/media/images/q2aanswers/332/kk1_1391575512898.jpg)
Find the term independent of x in the expansion of 〖〖(6x^2– 5/x^2 )]8. Binomial Theorem-Maths-Class-11
![Additional Math - Binomial Theorem - No term independent of x ⋆ Tuition with Jason - Math Specialist Additional Math - Binomial Theorem - No term independent of x ⋆ Tuition with Jason - Math Specialist](https://www.tuitionwithjason.sg/wp-content/uploads/2020/05/feature-image-binomial-find-term-independent-og-x.png)